Class 11 Physics Physical Quantity Notes

UNIT 1
CLASS 11 PHYSICS • MECHANICS

Physical Quantities

Chapter 1
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Measurement

The process of comparing an unknown physical quantity with a known fixed unit quantity is called measurement.

Physical Quantity

Those quantity which can be measured and can be expressed in numerical value are called physical quantity. For example: Mass, Length, Time, etc.

Physical Quantity = Numerical Value (N) × Unit (U)

The physical quantity can be divided into two parts:

  1. Fundamental Quantity
  2. Derived Quantity

Fundamental Quantity

The basic physical quantity which is taken as standard to measure other physical quantities is known as fundamental quantity.

For example: Length, mass, time, temperature, electric current, luminous intensity, amount of chemical substance.

Derived Quantity

A quantity obtained from fundamental quantities is called a derived quantity. For example: Area, volume, density, speed, electric intensity, etc.

Unit

The standard quantity in terms of which the given physical quantities can be compared is called unit. For example: kg, second, Newton, etc.

There are two types of unit:

  1. Fundamental Unit
  2. Derived Unit

Fundamental Unit

The units of fundamental quantities are called fundamental units. For example: kg, m, s, K, etc.

Derived Unit

The units of derived quantities are called derived units. For example: m/s, m/s2, etc.

System of Units

(i) F.P.S. System

In this system length is measured in foot, mass in pound and time in second. This is British system of units. Here, F → foot, P → pound, S → second.

(ii) MKS System

In this system, length is measured in metre, mass in kg, and time in second. This system was developed in France. Here, M → metre, K → kg and S → second.

(iii) CGS System

In this system, length is measured in centimetre, mass in gram and time in second. This system was developed in France. Here, C → centimetre, G → gram and S → second.

Characteristics of a Standard Unit

  1. It should be well defined and of a suitable size.
  2. It should be easily available, so that it can be easily reproduced in laboratories.
  3. It should not change with time and place.
  4. It should not change with change in physical condition.
  5. It should be universally agreed, so that result of measurement at different places can be compared.

SI System

The internationally standardised unit of measurement is called SI system.

In SI system of unit, 7 fundamental units and 2 supplementary units were proposed. These units are written below:

Fundamental Quantities S.I. Units Symbol
Lengthmetrem
Masskilogramkg
Timeseconds
TemperaturekelvinK
Luminous Intensitycandelacd
Electric CurrentampereA
Amount of Chemical Substancemolemol

Supplementary Quantities

Supplementary Quantity S.I. Unit Symbol
Plane angleradianrad
Solid anglesteradiansr

Dimensions of Physical Quantity

The power raised to the fundamental quantities which are involved in derived physical quantities is called dimension of physical quantity.

Dimensional Formula of Different Physical Quantities

1) Speed

Speed = distance / time

= [L] / [T]

= [LT−1]

∴ The dimensional formula of speed = [M0LT−1]

2) Velocity

Velocity = displacement / time

= [L] / [T]

= [LT−1]

∴ The dimensional formula of velocity = [M0LT−1]

From above, both speed and velocity have same dimensional formula. But speed is scalar quantity and velocity is vector quantity. Hence, from dimensional formula we cannot say physical quantity is scalar or vector.

Dimensional Equation

An equation containing physical quantities, each quantity is represented by its dimensional formula, the resulting equation is known as dimensional equation.

Next definition: When the dimension of a quantity is found and expressed in the form of an equation, the equation is called the dimensional equation.

Principle of Homogeneity of Dimension

The physical relations must obey the principle of homogeneity. According to this concept:

“Every term in a physical relation must have the same dimension.”

Suppose in physical relation, s = ut + ½at2, there are three terms: s, ut and ½at2. All the terms must have the same dimension, i.e.

[s] = [ut] = [½at2]

to obey the principle of homogeneity.

Table of Units and Dimensions of Fundamental Physical Quantities

S.N. Fundamental Physical Quantity Dimensional Formula SI Unit
1Mass[M]Kilogram
2Length[L]metre
3Time[T]second
4Temperature[K] or [θ]kelvin
5Electric Current[I] or [A]ampere
6Amount of Substance[N]mole (mol)
7Luminous Intensity[J]candela (cd)

A + B = C + D   /   or, A + B − C − D = 0

According to homogeneity:

dim. of A = dim. of B = dim. of C = dim. of D.

S.N. Physical Quantity Formula / Relation Dimensional Formula SI Unit
1Densitymass / volume[M L−3 T0]kg m−3
2Speed or Velocitydistance / time[M0 L T−1]m/s
3Accelerationvelocity / time[M0 L T−2]m/s2
4Momentummass × velocity[M L T−1]kg m s−1
5Forcemass × acceleration[M L T−2]N (Newton)
6PressureForce / area[M L−1 T−2]N m−2 or Pa
7Workforce × displacement[M L2 T−2]J (joule)
8EnergyWork (E = mc2)[M L2 T−2]J
9Gravitational Constant (G)force × d2 / (mass)2[M−1 L3 T−2]N m2 kg−2
10Surface Tensionforce / length[M L0 T−2]N m−1
11Moment of Inertiamass × (distance)2[M L2 T0]kg m2
12Angular Momentummoment of inertia × angular velocity[M L2 T−1]kg m2 s−1
13Torque or Coupleforce × perpendicular distance[M L2 T−2]N m
14Frequency1 / second[T−1]Hz
15Angular Velocity (ω)velocity / radius[T−1]s−1
16Specific Heatenergy / (mass × temperature)[M0 L2 T−2 K−1]J kg−1 °C−1
17Stressforce / area[M L−1 T−2]N/m2
18StrainΔl / l[L0] dimensionlessDimensionless
19Refractive IndexV1 / V2Dimensionless
20Mechanical AdvantageLoad / EffortDimensionless
21Electric ChargeI × t[M0 L0 T I]Amp-sec or Coulomb
22Electric ResistanceV / I[M L2 T−3 I−2]ohm (Ω) or volt/amp
23Boltzmann’s Constantenergy / temperature[M L2 T−2 K−1]J/K
24Planck’s Constant (h)E = hf[M L2 T−1]J·s or eV·s
25Power of Lens (P)P = 1/f[L−1]dioptre
26AngleDimensionlessrad

1) To Check the Correctness of a Physical Equation

Example: Check whether the physical equation v2 = u2 + 2as is dimensionally correct or not.

Given formula: v2 = u2 + 2as

[L.H.S.] = [v2] = [LT−1]2 = [L2T−2] …(i)

[R.H.S.] = [u2 + 2as]

= [LT−1]2 + [LT−2·L]

= [L2T−2] + [L2T−2]

Since the number 2 is dimensionless,

[R.H.S.] = [L2T−2] + [L2T−2] …(ii)

From equation (i) and (ii), [L.H.S.] = [R.H.S.]

Hence, the given equation is dimensionally correct.

2) To Derive the Relationship Between Different Physical Quantities

Example: Derive the dimensional relation of time period of pendulum with mass, length and acceleration due to gravity.

T ∝ lagb

or, T = k lagb …(i)

where k is dimensionless constant.

[T] = [L]a[LT−2]b

[M0L0T1] = [M0La+bT−2b]

Equating dimensions on both sides:

(i) 1 = −2b   ⇒   b = −½

(ii) a + b = 0   ⇒   a = ½

Putting the value of a and b in equation (i):

T = k l1/2g−1/2

T = k √(l/g)

3) To Convert a Unit From One System Into Another

Example: Convert 10 dyne into newton.

Let 10 dyne = N2 newton.

Here, dyne is the unit of force in CGS and newton in SI.

Dimensional formula of force = [MLT−2]

∴ a = 1, b = 1 and c = −2 in mass, length and time respectively.

CGS SystemSI System
N1 = 10 dyneN2 = ?
M1 = 1 gM2 = 1 kg
L1 = 1 cmL2 = 1 m
T1 = 1 sT2 = 1 s

According to the conversion formula:

N2 = N1 (M1/M2)a (L1/L2)b (T1/T2)c

N2 = 10 × (1g/1kg)1 × (1cm/1m)1 × (1s/1s)−2

= 10 × 10−3 × 10−2 × 1

10 dyne = 10−4 N

4) To Determine the Dimension of a Constant

Example: Determine the dimension of universal gravitational constant (G).

We have, F = Gm1m2 / r2

or, G = Fr2 / (m1m2)

= [MLT−2][L2] / ([M][M])

[G] = [M−1L3T−2]

Hence, the dimensions of G are −1 in mass, 3 in length and −2 in time.

Example: Find the dimensional formula of coefficient of viscosity.

We have, F = 6πηrv

η = F / (6πrv)

= [MLT−2] / ([L][LT−1])

[η] = [ML−1T−1]

Hence, the dimensional formula of coefficient of viscosity is [ML−1T−1].

5) To Establish Relationship Between Different Physical Quantities

Example: The centripetal force depends upon mass, velocity and radius of circular path.

Then, F ∝ mavbrc

F = k mavbrc …(i)

where k is dimensionless constant.

[MLT−2] = [M]a[LT−1]b[L]c

[MLT−2] = [MaLb+cT−b]

Equating dimensions on both sides:

(i) a = 1

(ii) −b = −2   ⇒   b = 2

(iii) b + c = 1   ⇒   2 + c = 1   ⇒   c = −1

F = k(mv2/r) = mv2/r

Q.1 (A)

If v = a + bt, where v is velocity and t is time, then find dimension of ‘a’ & ‘b’.

v = a + bt

or, v − a − bt = 0

According to homogeneity:

dim. of a = dim. of v = [LT−1]

∴ dim. of a = [M0LT−1]

dim. of bt = dim. of v

b × T = LT−1

b = L/T2 = [LT−2]

∴ dim. of b = [M0LT−2]

Q.1 (B)

If x = a + c/m where x = displacement, m = mass, find the dimension of ‘a’ & ‘c’.

We have, x = a + c/m

or, x − a − c/m = 0

According to homogeneity:

Dim. of a = dim. of x = L

∴ Dim. of a = [M0LT0]

Dim. of c/m = dim. of x

c/M = L

or, c = ML

∴ Dim. of c = [MLT0]

Q.1 (C)

If μ = A + B/λ2, where μ = refractive index or dimensionless quantity and λ = wavelength (L), find the dimension of ‘A’ & ‘B’.

Given, μ − A − B/λ2 = 0

According to homogeneity:

∴ dim. of A = [M0L0T0]

dim. of B/λ2 = dim. of μ

B/[L2] = [M0L0T0]

or, B = [M0L2T0]

∴ dim. of B = [M0L2T0]

Q.1 (D)

Find dim. of x if y = tan(xt), where t is time.

Given, y = tan(xt)

dim. of xt = [M0L0T0]

x × T = [M0L0T0]

∴ x = [M0L0T−1]

Q.1 (E)

If P = a(r²x), find dim. of x, where r is radius.

Given, P = a(r²x)

We know, power → dimensionless.

i.e., dim. of r2x = [M0L0T0]

x[L2] = [M0L0T0]

or, x = [M0L−2T0]

Q.2

Find the dimensional formula of potential difference.

Potential Difference = W/Q = (F × displacement)/(I × t)

= [MLT−2][L] / ([A][T])

[V] = [ML2T−3A−1]

Q.3

Find the dimensional formula of resistance.

Resistance = V/I = W/(Q × I)

= W/(I × t × I)

= (F × displacement)/([I2][T])

[R] = [ML2T−3A−2]

  1. It cannot give information about dimensionless constant involved in a physical relation.
  2. It is very difficult to derive the dimensional relation between more than three physical quantities.
  3. It cannot be used to derive the relation involving trigonometric, exponential and logarithmic functions.
  4. It can’t tell us whether a quantity is vector or scalar.
  5. The dimensionally correct relation may not be physically correct.

Error

The difference between standard value and observed value of a physical quantity is called error.

Error = Standard Value − Observed Value
Note: The measurement of a physical quantity is expressed as x ± y, where x is observed value and y is error, which means the standard value of this measurement lies between (x + y) to (x − y).

Example

The measurement of resistance of a conductor is expressed as (10 ± 5%) Ω. What does it mean?

The measurement of resistance of a conductor is expressed as (10 ± 5%) Ω, which means 10 Ω is observed value and 5% is error, so the standard value of this resistance lies between (10 − 0.05) Ω to (10 + 0.05) Ω.

Types of Error

(a) Systematic Error

The error introduced due to the limitation of the formula used and fault in the instrument is called systematic error.

(b) Random Error

The error introduced due to the carelessness of the experiment and unfavourable condition of the environment such as temperature, pressure and humidity etc. is called random error.

Accurate Measurement

The measurement in which observed value of any physical quantity is closer to the standard value of that physical quantity is called accurate measurement.

Example

Standard value of g in lab is 9.8 m/s2. The measured value of g is obtained as 9.67 m/s2 and 9.79 m/s2. The value of 9.79 m/s2 is very close to the standard value, so it is more accurate than the value 9.67 m/s2.

Precise Measurement

The measurement in which the observed value of a physical quantity can be reproduced again and again by repeated experiment and procedure is called precise measurement.

If the readings are very close to each other, they are called precise readings. The thickness of a glass plate measured by spherometer are 2.43 mm, 2.44 mm, 2.42 mm and 2.44 mm. These readings are very close to each other. So they are precise measurement.

Least Count

The uploaded scan shows only the heading “Least Count” at the bottom of page 16; its definition or continuation is not present in the supplied 17-page PDF.

Significant Figure

The meaningful digits of a number are called significant figure. Significant figure depends on the least count of a measuring device.

Example

Let us take the length of rod by a ruler for three times. Readings are obtained as 10.2 cm, 10.3 cm and 10.3 cm. So mean length:

Mean length = (10.2 + 10.3 + 10.3) / 3

= 10.266666 cm

Hence, all digits are not significant; only first three digits are significant. The length of rod is taken as 10.2 cm or 10.3 cm.

Question

The length of a rod is exactly 1 cm. An observer records the reading as 1.0 cm, 1.00 cm and 1.000 cm. Which is most accurate measurement?

Length = (1.0 + 1.00 + 1.000) / 3 = 3.000 / 3 = 1.000

Hence the length of rod = 1.0 or 1.00.

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